To determine the approximate time of each Earth history event in terms of the
1998 calender, I simply set up the given dates as a simple equation and 
worked off of that.

For example:

	Approximately 225 million years ago, the last trillobytes died.  To 
	find out where this date falls under the 1998 calendar, I used the 
	scale 365 days = 4.6 billion years, and set up the equation like 
	so...

		# of days = # of years in billions
		# of days = # of years in billions

	or...

		365 = 4.6
		 x  = .225

	Solve for the variable x and the answer is...
		
		17.85326087

	And since the terms are in days, and 365 is the equivalent of 
	January 1, 1998  12:00 a.m., 17 - the whole number - is equal to 17 
	days from the December 31, 1998 12:00 a.m.  To solve for hours, I 
	multiplied the decimal remainder by 24 hours (# of hours in a day)
 	like so...

		0.85326087 x 24 = 20.47826088

	So now, I know that approximately 17 days and about 20 hours from 
	December 31, 1998 (12:00:00 a.m.), the trillobytes died.  To find 
	out the number of minutes in from 12/31/98, I again took the decimal 
	remainder and multiplied it by 60 (# of minutes in an hour) like 
	so...

		0.47826088 x 60 = 28.6956528

	To find the # of seconds, I repeated the process above of taking the 
	decimal remainder and multiplying it by 60 since there are also 60 
	seconds in 1 minute.  The final approximate answer is...

		17 days, 20 hours, 28 minutes, and 42 seconds from December 
		31, 1998 12:00:00 a.m.

	To find out the date on the calander, I simply subtracted and counted
	backwards like so...

		24 - 20 = 4
		60 - 28 = 32
		60 - 42 = 18

	So, the final answer is that the trillobytes died on Monday, December
	14, 1998 at approximately 4:32:18 a.m.